[XSL-LIST Mailing List Archive Home]
[By Thread]
[By Date]
On 10/17/06, Abel Braaksma <abel.online@xxxxxxxxx> wrote:
<xsl:param name="path" select="'../../'" as="xs:string"/>
and
href="{$path}existingpath"
Re: [xsl] Referring to stylesheet itself, possible in XSLT 1.0, but how in XSLT 2.0?
Subject: Re: [xsl] Referring to stylesheet itself, possible in XSLT 1.0, but how in XSLT 2.0? From: "Andrew Welch" <andrew.j.welch@xxxxxxxxx> Date: Tue, 17 Oct 2006 14:45:21 +0100 |
On 10/17/06, Abel Braaksma <abel.online@xxxxxxxxx> wrote:
David Carlisle wrote: > Incidentally, why do you want to use document('')??
No reason in particular, other than getting the stylesheet that is currently being executed. I tried all sorts of ideas and combinations of ideas, but the result is simple: it cannot be done once you have the xsl:stylesheet offset to some directory where your current stylesheet does not reside.
So, if your stylesheet uses something like this: <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0" xml:base="../..">
but is itself not at location "../..", all bets are off for getting the location of the current stylesheet.
Instead of using xml:base why not just create a parameter $path and then modify all of your paths in the stylesheet to contain that parameter, eg:
<xsl:param name="path" select="'../../'" as="xs:string"/>
and
href="{$path}existingpath"
cheers andrew
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
Re: [xsl] Referring to stylesheet i, Abel Braaksma | Thread | Re: [xsl] Referring to stylesheet i, Abel Braaksma |
Re: [xsl] zap some node s and chang, Davide Antoni | Date | Re: [xsl] Question about table colu, ms |
Month |