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[xsl] Is it possible to create xsl:sort from input parameters using XSL T 2.0 (Saxon)?

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Hi,

I am trying to create dynamic sorts in my XSLT file so the end user can
select different fields to sort the data on then rerun the XSLT. 

The XSLT is called from a vb.net app where the chosen sort fields are passed
as XML into a param called sortField:

<SortFields>
	<SortField DataType="number" CaseOrder="lowercasefirst"
Order="ascending">lenderid</SortField>
	<SortField DataType="number" CaseOrder="lowercasefirst"
Order="ascending">generalproductid</SortField>
</SortFields>

Using the following XSL:

	<xsl:for-each select="$tempRoot/product">
		<xsl:choose>
			<xsl:when test="boolean($sortField)=true">
				<xsl:for-each
select="$sortField/SortFields/SortField">
					<xsl:sort select="." order="@Order"
data-type="@DataType" case-order="@CaseOrder" />
				</xsl:for-each>

			</xsl:when>
		</xsl:choose>
	</xsl:for-each>


which (in my head at least) would result in something akin too: 

	<xsl:for-each select="$tempRoot/product">
		<xsl:sort select="lenderid" order="ascending"
data-type="number" case-order="lowercasefirst"/>
		<xsl:sort select="generalproductid" order="ascending"
data-type="number" case-order="lowercasefirst"/>
	</xsl:for-each>	


The main input XML document which is being transformed looks like this:

<root>
	<product>
		<lenderid>1234</lenderid>
		<generalproductid>12344321</genrealproductid>
		<lendername>fred</lendername>
		 ...
 	</product>
	<product>
		...
	</product>
</root>


Having tried doing it I'm now pretty sure that this isn't possible as I get
a compile error on the xsl:sort order as it is expecting ascending or
descending.

Is there any other way of achieving this?


Cheers

Nick




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