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If I have declared a processor and I want to pass parameters collected from a form in an HTML page to my XSL stylesheet, isn't it as simple as the example below?
If I use alert(processor.getParameter(null, "type")) the parameter value is null, and the transformation fails because nothing was passed into the XSL stylesheet.
Re: [xsl] XML subset selection-a simpler way? (message 27746)
Subject: Re: [xsl] XML subset selection-a simpler way? (message 27746) From: "Alan Varga" <aevarga@xxxxxx> Date: Wed, 28 Jun 2006 07:30:02 -0500 |
If I have declared a processor and I want to pass parameters collected from a form in an HTML page to my XSL stylesheet, isn't it as simple as the example below?
~~~~~ start of Javascript snippet ~~~~~ var sCalType = checkRadio(theForm.grpOptions); var sSelection = theForm.lstCalendar.value; var xslStylesheet = "test.xsl"; ... var xslDoc = Sarissa.getDomDocument(); xslDoc.async = false; xslDoc.load(xslStylesheet);
var processor = new XSLTProcessor(); processor.importStylesheet(xslDoc); processor.setParameter(null, "type", sCalType); processor.setParameter(null, "selection", sSelection); ... function checkRadio(group){ for (x=0; x<group.length; x++) { if (group[x].checked == true) { val = group[x].value; // alert(val); } } return val; } ~~~~~ end of Javascript snippet ~~~~~
~~~~~ start of XSL snippet ~~~~~ <xsl:param name="type"/> <xsl:param name="selection"/> ... <xsl:template match="Events"> <tbody> <xsl:choose> <xsl:when test="$type='Month'"> <xsl:apply-templates select="Event[MonthName=$selection]" /> </xsl:when> <xsl:when test="$type='Band'"> <xsl:apply-templates select="Event[Band=$selection]" /> </xsl:when> </xsl:choose> </tbody> </xsl:template> ... ~~~~~ end of XSL snippet ~~~~~
If I use alert(processor.getParameter(null, "type")) the parameter value is null, and the transformation fails because nothing was passed into the XSL stylesheet.
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