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Ohh, was simpler that I was trying to do incrementing a variable. Anyway, I have seen some examples and some e-mails on the list regarding to how increment a variable and If I'm not wrong there is no possibility of incrementing inside a for-each loop, so sometimes you need to change the xsl code only to make this feature working.
I have seen that in XSLT 2.0 we have an incremental function but I'm a newbie even in XSLT 1.0 so do you recommend to use version 2.0 instead of 1.0? Does this version a lot of improvements against version 1.0?
Anyone have a good and very simple example, a link or something that explains this "problem"?
David Carlisle wrote:
Re: [xsl] Counting total of groups
Subject: Re: [xsl] Counting total of groups From: Francisco <francisco@xxxxxxxxxxxxxx> Date: Thu, 01 Jun 2006 11:50:32 +0100 |
Ohh, was simpler that I was trying to do incrementing a variable. Anyway, I have seen some examples and some e-mails on the list regarding to how increment a variable and If I'm not wrong there is no possibility of incrementing inside a for-each loop, so sometimes you need to change the xsl code only to make this feature working.
I have seen that in XSLT 2.0 we have an incremental function but I'm a newbie even in XSLT 1.0 so do you recommend to use version 2.0 instead of 1.0? Does this version a lot of improvements against version 1.0?
Anyone have a good and very simple example, a link or something that explains this "problem"?
Regards Francisco
David Carlisle wrote:
I need to have that the number of groups is 3.
which is the number of things selected by <xsl:for-each select="product[count(. | key('hotelname', name)[1]) = 1]">
so
<xsl:variable name="grps" select="product[count(. | key('hotelname', name)[1]) = 1]">
no of groups is <xsl:value-of select="count($grps)"/> <xsl:each select="$grps"> ....
or, if you only need the number withing the for-each you don't need to count you can use last() like:
<xsl:for-each select="product[count(. | key('hotelname', name)[1]) = 1]"> group <xsl:value-of select="position()"/> out of <xsl:value-of select="last()"/> ...
David
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