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Re: [xsl] Sorting an xml

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The printout for this should be sorted by <place> like this:
Kyl och frys:
Lax 8 st
Grddde 1,2 l

Frukt och grvnt:
Chalottenlvk 4 st

Vvrigt:
Matlagningsvin 0,66  l

It would be easier to understand if you give what output xml you are
looking for.

you can try:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
	<!-- default identity translation -->
	<xsl:template match="*|@*|comment()|processing-instruction()|text()">
		<xsl:copy>
			<xsl:apply-templates
select="*|@*|comment()|processing-instruction()|text()"/>
		</xsl:copy>
	</xsl:template>
	<!-- start processing with the root element  -->
	<xsl:template match="shopinglist">
		<xsl:copy>
			<xsl:apply-templates select="item">
				<xsl:sort select="place"/>
			</xsl:apply-templates>
		</xsl:copy>
	</xsl:template>
</xsl:stylesheet>

It will reorder the source xml item elements according to the "place"


--

Jagdishwar B.

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