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[xsl] XML transformation to RDF with XSLT help

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Hello.
I'm working on a xml transformation to RDF with XSLT help.

I'm totally very new to XSLT. And It's hard and I'm stuck now. I need your help.

Here are xml element representation with three ways.
<gemq:teachingMethods xsi:type='dcterms:URI'>http://purl.org/gem/instance/GEM-TM/#PeerTutoring</gemq:teachingMethods>
<gemq:teachingMethods xsi:type='gemq:GEM-TM'>Thematic approach</gemq:teachingMethods>
<gemq:teachingMethods>MultimediaInstruction</gemq:teachingMethods>

I need to transform this to rdf like this
With xsi:type="dcterms:URI"
<rdf:Description>
<gemq:teachingMethods rdf:resource="http://purl.org/gem/instance/GEM-TM/#PeerTutoring"/>
</rdf:Description>

With xsi:type="gemq:GEM-TM"
<rdf:Description>
<gemq:teachingMethods>
  <gemq:GEM-TM>
    <rdf:value>Thematic approach</rdf:value>
    <rdfs:label>Thematic approach</rdfs:label>
  </gemq:GEM-TM>
</gemq:teachingMethods>
</rdf:Description>

And with just free-text
<rdf:Description>
   <gemq:teachingMethods>MultimediaInstruction</dc:identifier>
 </rdf:Description>

I did xslt with
<xsl:template match="gemq:teachingMethods">
		<xsl:choose>
			<xsl:when test="contains(@xsi:type, 'dcterms:URI')">
			  <xsl:attribute name="rdf:resource">
				  <xsl:value-of select="normalize-space(.)"/>
			 </xsl:attribute>
			</xsl:when>
			<xsl:when test="not[@xsi:type]">
			  <xsl:attribute name="rdf:resource">
				  <xsl:value-of select="normalize-space(.)"/>
			 </xsl:attribute>
			</xsl:when>
		<xsl:otherwise>
			<gemq:teachingMethods>
					<xsl:value-of select="normalize-space(.)"/>
			</gemq:teachingMethods>
		</xsl:otherwise>
	</xsl:choose>
	</xsl:template>

Could you give me some tips or advice?

I appreciate it.

Thanks a lot,

Best regards,
Oknam

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