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Re: [xsl] Selecting the Latest Date
Subject: Re: [xsl] Selecting the Latest Date From: Mukul Gandhi <gandhi.mukul@xxxxxxxxx> Date: Wed, 8 Feb 2006 09:40:24 +0530 |
You may try something like this <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xsl:output method="text" /> <xsl:template match="/data"> <xsl:for-each select="items/date"> <xsl:sort select="translate(., '.', '')" order="descending" data-type="number" /> <xsl:if test="position() = 1"> <xsl:value-of select="." /> </xsl:if> </xsl:for-each> </xsl:template> </xsl:stylesheet> Regards, Mukul On 2/8/06, jeb501@xxxxxxxxxxxxxxx <jeb501@xxxxxxxxxxxxxxx> wrote: > Hi all, > > From the below XML file how to pick the late date from date node.. > > <?xml version="1.0" encoding="Windows-1252" standalone="yes" ?> > - <data> > - <items> > <ref>28834</ref> > <pdate>01.02.2006</pdate> > <qty>5</qty> > <clno>ax588</clno> > <date>01.02.2006</date> > <clrf>Normal 1</clrf> > <clno>bx588</clno> > <date>03.02.2006</date> > <clrf>Normal 2</clrf> > <clno>bx588</clno> > <date>06.02.2006</date> > <clrf>Normal 3</clrf> > </items> > </data> > > Regards > Eugene
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