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Hi all
Someone kindly gave me the following stylesheet to reproduce a SQL BTree in XML nodes. I'm having a problem, however, and need to convert the template to act on <xsl:call-template /> rather than <xsl:apply-templates />. Can someone help me convert it? I've tried, but I just end up with 500 errors from PHP5.
:::::
<xsl:output method="xml" encoding="utf8" indent="yes"/>
</xsl:stylesheet>
[xsl] Convert apply-templates to call-template?
Subject: [xsl] Convert apply-templates to call-template? From: Phillip B Oldham <phillip.oldham@xxxxxxxxxx> Date: Mon, 30 Jan 2006 08:11:34 +0000 |
Hi all
Someone kindly gave me the following stylesheet to reproduce a SQL BTree in XML nodes. I'm having a problem, however, and need to convert the template to act on <xsl:call-template /> rather than <xsl:apply-templates />. Can someone help me convert it? I've tried, but I just end up with 500 errors from PHP5.
:::::
<?xml version="1.0" encoding="utf8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" encoding="utf8" indent="yes"/>
<!-- Conditions equivalent to <xsl:sequence select="$boss/../item[lh gt $boss/lh and rh le $boss/rh]"/> -->
<xsl:template match="item"> <xsl:param name="context"/> <xsl:if test="not($context[current()/lh > lh and rh >= current()/rh])"> <xsl:variable name="context-inner" select="$context[lh > current()/lh and current()/rh >= rh]"/> <department title="{name}"> <xsl:apply-templates select="$context-inner"> <xsl:with-param name="context" select="$context-inner"/> </xsl:apply-templates> </department> </xsl:if> </xsl:template>
<xsl:template match="/"> <group> <xsl:apply-templates select="output/item"> <xsl:with-param name="context" select="output/item"/> </xsl:apply-templates> </group> </xsl:template>
</xsl:stylesheet>
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