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Re: [xsl] finding lowest level in ancestor:: axis

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> <xsl:variable name="parent"
>     select="id(@idref)/ancestor::div10 |

Thi selects a node set of all the relevant elements. As the name "set"
implies node sets are unordered, so it makes no difference how you
arrange the terms with | .  | is set union and a | b is the same as b | a.

However generate-id() takes a single node and returns its id so if you
give it a node set, as with most xslt1 functions, it sorts the nodes
into document order and uses the 1st node,silently discarding the rest.

I think you want $parent to be the nearest ancestor of the idrefed node
whose name starts with div so that's

select="id(@idref)/ancestor-of-self::*[starts-with(local-name(),'div')][1]"

David

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