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RE: [xsl] apply templates to all attributes except for one
Subject: RE: [xsl] apply templates to all attributes except for one From: "Michael Kay" <mike@xxxxxxxxxxxx> Date: Sun, 8 Jan 2006 14:16:24 -0000 |
> > Or of course you can write > > > > <xsl:template match="@foo"/> > > > > with xsl:apply-templates select="@*" > > I'm not sure whether that applies to my case, here's the XSLT: You can use the technique, but you'll need to use different modes for the two apply-templates calls. Michael Kay http://www.saxonica.com/ > > <xsl:transform version="1.0" > xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> > <xsl:template match="node()|@*"> > <xsl:copy> > <xsl:apply-templates select="node()|@*"/> > </xsl:copy> > </xsl:template> > <xsl:template match="para[@foo]"> > <para> > <xsl:apply-templates > select="@*[not(local-name()='foo')]"/> > <bar> > <xsl:apply-templates select="@foo"/> > </bar> > <xsl:apply-templates select="node()"/> > </para> > </xsl:template> > <xsl:template match="para/@foo"> > <xsl:value-of select="."/> > </xsl:template> > </xsl:transform> > > Tobi > > > > -----Original Message----- > [...] > > > Hi > > > > > > In an XSLT I have the following: > > > > > > <xsl:apply-templates select="@*[not(local-name()='foo')]"/> > > > > > > It works. But is there a more elegant (or at least shorter) > > > way to write this? > > > > > > Tobi
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