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RE: [xsl] trouble with preceding axis

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You might select the nearest preceding sibling like this,

        <xsl:for-each select="/root/orange/preceding-sibling::*">
            <xsl:if test="position() = last()">
                <xsl:value-of select="name(.)"/>
                 ...
            </xsl:if>
        </xsl:for-each>


Hope this is what you want.

Lisa


-----Original Message-----
From: Duane Gran [mailto:duane.gran@xxxxxxxxx]
Sent: Tuesday, January 03, 2006 1:20 PM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Re: [xsl] trouble with preceding axis

Lisa,

Thank you very much.  If you don't mind, I've run into another issue
today with referencing the preceding element.  Here is an example:

<root>
   <apple/>
   <pear/>
   <orange/>
</root>

Given an xpath to orange (/root/orange) I want to reference the
previous element which is a peer.  I tried the following with no
success:

   /root/preceding::orange

I'm sure this is dreadfully simple, but I'm drawing a blank and I'm
not seeing the answer in the tutorials I'm reading.

Duane

On Jan 3, 2006, at 2:52 PM, Xia Li wrote:

> If you want to select the preceding <item> element of the <item>
> element
> whose child <label> element satisfies the predicate [label =
> 'subTitle'], you might try the following XPath expression,
>
> //item[label = 'subTitle']/preceding::item
>
> Lisa
>
>
> -----Original Message-----
> From: Duane Gran [mailto:duane.gran@xxxxxxxxx]
> Sent: Tuesday, January 03, 2006 10:35 AM
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: [xsl] trouble with preceding axis
>
> I'm having some trouble using the preceding axis in XPath and would
> be much obliged if someone could steer me in the right direction.  I
> have the following document:
>
> <root>
>    <item order="3">
>      <label>Title</label>
>    </item>
>    <item order="4">
>      <label>subTitle</label>
>    </item>
> </root>
>
> I have the following XPath to select the second item, based on the
> value of its label child:
>
>    //item[label = 'subTitle']
>
> Now I want to modify this so that I refer to the preceding item
> element, the first one in the list.  I tried the following without
> success (it returns the second item element):
>
>    //preceding::item[label = 'subTitle']
>
> Suggestions are most welcome on this.
>
> Duane

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