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Re: [xsl] xsl:key only checks first child, need to check all
Subject: Re: [xsl] xsl:key only checks first child, need to check all From: Ragulf Pickaxe <ragulf.pickaxe@xxxxxxxxx> Date: Fri, 28 Oct 2005 10:00:15 +0200 |
Hi Patrick, > Which obviously would cause the problem I described. But that '[1]' was left over from me debugging. Sorry about that. It doesn't really matter whether it's there or not - I get the same results. So obviously [1] is the default when no explicit expression is given. The problem is that I can't figure out how to select all, something like [*]. Obviously [1] is not the default in general. What you get is a nodeset containing all contains elements in the given structure. When you use the concat function, you get a string as an output. Because of this, the nodeset is converted to a string using the rules for this - meaning that you get the string value of the first element in the nodeset. Ragulf Pickaxe :-)
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