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If you include also / in the match:
<xsl:template match="/ | @* | node()">
I think it should work in the same way
works.
Joris Gillis wrote:
Re: [xsl] Strict sequential identity rule?
Subject: Re: [xsl] Strict sequential identity rule? From: George Cristian Bina <george@xxxxxxx> Date: Wed, 21 Sep 2005 16:49:23 +0300 |
If you include also / in the match:
<xsl:template match="/ | @* | node()">
I think it should work in the same way
<xsl:template match="node() | @*"> <xsl:copy> <xsl:apply-templates select="node() | @*"/> </xsl:copy> </xsl:template>
works.
Best Regards, George --------------------------------------------------------------------- George Cristian Bina <oXygen/> XML Editor, Schema Editor and XSLT Editor/Debugger http://www.oxygenxml.com
Joris Gillis wrote:
Tempore 15:20:04, die 09/21/2005 AD, hinc in xsl-list@xxxxxxxxxxxxxxxxxxxxxx scripsit David Carlisle <davidc@xxxxxxxxx>:
I'd say FALSE, because it cannot handle this XML document properly:
it can so:-)
The result of the transformation is:
<!-- foo --> <bar>baz</bar> <bar>baz</bar>
This is not even well-formed XML anymore. How can you still call it an identity transformation, when it gives this behaviour?
regards,
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