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Hi,
Tempore 10:39:52, die 09/08/2004 AD, hinc in xsl-list@xxxxxxxxxxxxxxxxxxxxxx scripsit Shailesh <shailesh@xxxxxxxxxxxx>:
Try applying the following stylesheet to 'source.xml'.
<xsl:output method="xml" />
</xsl:stylesheet>
Re: [xsl] Get value from update.xml and stored in source.xml(update source.xml)
Subject: Re: [xsl] Get value from update.xml and stored in source.xml(update source.xml) From: "Joris Gillis" <roac@xxxxxxxxxx> Date: Thu, 08 Sep 2005 10:56:19 +0200 |
Hi,
Tempore 10:39:52, die 09/08/2004 AD, hinc in xsl-list@xxxxxxxxxxxxxxxxxxxxxx scripsit Shailesh <shailesh@xxxxxxxxxxxx>:
Using xslt 1.0 I have to extract the value of <test2> which is in <test1 id="0000001"> of update.xml and put it in <test2> which is in <test1 id="0000001"> of source.xml.
This should updates the <test2> of source.xml without any other changes.
Try applying the following stylesheet to 'source.xml'.
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xsl:output method="xml" indent="yes"/> <xsl:strip-space elements="*"/>
<xsl:output method="xml" />
<xsl:variable name="update" select="document('update.xml')"/> <xsl:key name="id" match="*" use="@id"/>
<xsl:template match="*[@id]"> <xsl:variable name="id" select="@id"/> <xsl:copy> <xsl:apply-templates select="@*" /> <xsl:for-each select="$update"> <xsl:copy-of select="key('id',$id)/*"/> </xsl:for-each> </xsl:copy> </xsl:template>
<xsl:template match="node()|@*"> <xsl:copy> <xsl:apply-templates select="node()|@*" /> </xsl:copy> </xsl:template>
</xsl:stylesheet>
-- Joris Gillis (http://users.telenet.be/root-jg/me.html) Deserta faciunt et innovationem appelant
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