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Try using a key like this:
Re: [xsl] Problem using Key on multiple elements
Subject: Re: [xsl] Problem using Key on multiple elements From: "Joris Gillis" <roac@xxxxxxxxxx> Date: Fri, 12 Aug 2005 22:49:11 +0200 |
Hi, Tempore 15:20:00, die 08/12/2005 AD, hinc in xsl-list@xxxxxxxxxxxxxxxxxxxxxx scripsit Sreenath Juluri <jssreenath@xxxxxxxxx>:
My source xml looks something like this. ... Ill-formed XML
An attempt to construct well-formed XML out of it (please correct the namespace) <xtvd xmlns="a"> <productionCrew> <crew program="EP3297910048"> <member> <role>Actor</role> <givenname>Peter</givenname> <surname>McCauley</surname> </member> <member> <role>Actor</role> <givenname>Michael</givenname> <surname>Sinelnikoff</surname> </member> </crew> <crew program="EP3556823923"> <member> <role>Director</role> <givenname>Michael</givenname> <surname>Sinelnikoff</surname> </member> <member> <role>Actor</role> <givenname>Michael</givenname> <surname>Offer</surname> </member> <member> <role>Executive Producer</role> <givenname>John</givenname> <surname>Landis</surname> </member> </crew> </productionCrew> </xtvd>
Now in my transformed xml there should be only one element for each person irrespective of the role. for eg in the above piece of xml there shud b only one element for Michael Sinelnikoff.
Try using a key like this:
<xsl:key name="roleNames" match="a:xtvd/a:productionCrew/a:crew/a:member" use="concat(a:givenname,'+',a:surname)"/>
and a loop like this: <xsl:for-each select="a:xtvd/a:productionCrew/a:crew/a:member [generate-id()=generate-id(key('roleNames', concat(a:givenname,'+',a:surname))[1])] /a:givenname"> </xsl:for-each>
regards, -- Joris Gillis (http://users.telenet.be/root-jg/me.html) B+N N1N;N.N8N5N9N1 N:N1N9 ON? N;N,N4N9 ON,N=ON1 N2N3N1N/N=N?ON= N1OO ON,N=O B;
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