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Re: [xsl] Flat to hierarchical with for-each-group (XSLT 2.0 solution)

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> The only mystery to me is why I had to use test="current-group()[1]/name() 
> = 'heading2'" 

It's best not to use name() (especially if there is any possibility of
namespaces being involved) as name() isn't guaranteed to return the
prefix that you expect, and you are not supposed to care about prefixes
anyway.
"current-group()[1]/self::heading2"
is your friend.


> rather than test="current-group()/heading2" 

that tests if any node in the current group has a heading2 child rather
than testing if it is a heading2.

> just test="heading2"

That tests if the current node has a heading2 child. 

David

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