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[xsl] conditional position()
Subject: [xsl] conditional position() From: Bruce D'Arcus <bdarcus@xxxxxxxxx> Date: Wed, 20 Apr 2005 15:49:54 -0400 |
Hi All, Been away wrapping up a book that I'm formatting with the XSLT code that I developed with much help from this list. Alas, there's still work to be done there. How do I get this position() function to apply only to only certain nodes? Here's my expression: <xsl:when test="$contributor-role='primary' and position() = last()"/> I know why the above doesn't work, but I'm not sure how to fix it. Am using XSLT 2.0. The (global) contributor-role variable is: <xsl:variable name="primary-contributors" select="('author', 'editor', 'creator', 'reporter')"/> Source example would be: <name type="personal"> <namePart type="given">Jane</namePart> <namePart type="family">Doe</namePart> <role> <roleTerm>translator</roleTerm> </role> </name> <name type="personal"> <namePart type="given">Jane</namePart> <namePart type="family">Doe</namePart> <role> <roleTerm>author</roleTerm> </role> </name> <name type="personal"> <namePart type="given">John</namePart> <namePart type="family">Smith</namePart> <role> <roleTerm>translator</roleTerm> </role> </name> The position of the second name element with the author role should be '1' and it should be 'true' for last(). In other words, processing should completely ignore the name elements that contain roles other than those that are "primary." How best to do this? Bruce
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