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Re: [xsl] sort order elements
Subject: Re: [xsl] sort order elements From: David Carlisle <davidc@xxxxxxxxx> Date: Wed, 30 Mar 2005 17:47:34 +0100 |
from the following xml database i am trying to output elements in reverse order : well actually you seem to want to keep the element nodes in the same order but swap round thir children so something like <xsl:template match="car"> <xsl:copy> <xsl:for-each select="*"> <xsl:variable name="x" select="position()"/> <xsl:copy> <xsl:copy-of select="../*[last()+1-$x]/*"/> </xsl:copy> </xsl:for-each> </xsl:copy> </xsl:template> David ________________________________________________________________________ This e-mail has been scanned for all viruses by Star. The service is powered by MessageLabs. For more information on a proactive anti-virus service working around the clock, around the globe, visit: http://www.star.net.uk ________________________________________________________________________
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