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Subject: [xsl] in this xsl , why dont get result with substring-before .. From: henry human <henry_human@xxxxxxxx> Date: Fri, 25 Mar 2005 14:37:52 +0100 (CET) |
Problem number 1)i have this two files. when i try to get with substring-before or substring-after i get no data Problem number 2) why i get in this for-each loop only one time the content of workstep1 node Problem number 3) what is the other alternativity to call a template in this loop instead of to use xsl:apply-templates ? thanks <?xml version='1.0'?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="html"/> <xsl:template match="/Job"> <html><head><META http-equiv="Content-Type" content="text/html; charset=iso-8859-1"/> </head><body> <table> <tr> <td></td> <td> <b>JOB Desc. </b></td></tr> <xsl:for-each select="Jobsdetails"> <tr> <td></td> <td> <xsl:value-of select="jobDescription"/></td> </tr> <xsl:apply-templates select="worksPart1"/> </xsl:for-each> </table></body></html> </xsl:template> <xsl:template match="worksPart1" > <tr> <td></td> <td> <xsl:if test="contains(bbb,'RRR')"> <xsl:value-of select="substring-before('bbb','RRR')"/> +<xsl:value-of select="substring-after('bbb','RRR')"/> </xsl:if> </td> </tr> </xsl:template> </xsl:stylesheet> ------------------------------------------ <?xml version="1.0"?> <?xml-stylesheet type="text/xsl" href="test.xsl"?> <Job> <Jobsdetails> <jobDescription>mydescription</jobDescription> <worksPart1> <bbb>beforeRRRafter</bbb> <worksNr>20362</worksNr> </worksPart1> </Jobsdetails> </Job> ___________________________________________________________ Gesendet von Yahoo! Mail - Jetzt mit 250MB Speicher kostenlos - Hier anmelden: http://mail.yahoo.de
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