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Re: [xsl] Sorting network addresses


Subject: Re: [xsl] Sorting network addresses
From: Craig W <codecraig@xxxxxxxxx>
Date: Wed, 2 Mar 2005 09:12:28 -0500

well, i changed the xslt version from 2.0 to 1.0 and i get the correct
output....i wonder why?  FYI, XMLSpy be default uses its own XSLT
engine (for either 1.0 or 2.0), or you can specify that it uses
Microsoft's XML parser, or you can have it use some other XSL
transformation program that you specify.

Anyway, thanks for the help....it would still be nice to know why
version 2.0 is acting differently.

-Craig


On Wed, 2 Mar 2005 14:05:20 GMT, David Carlisle <davidc@xxxxxxxxx> wrote:
> 
> 
> > ....now do u get what i get?
> no I get:
> 
> $ saxon ip2.xml ip2.xsl
> <?xml version="1.0" encoding="UTF-8"?>
> <networks>
> <network>
> <address>1.1.1.1</address>
> </network>
> <network>
> <address>2.3.1.2</address>
> </network>
> <network>
> <address>170.5.2.4</address>
> </network>
> </networks>
> 
> But I just noticed that you are specifying XSLT2 (although you don't have
> any xslt2 specific features) so I'll try with saxon8:
> 
> I get same:
> 
> $ java -jar ../saxon8/saxon8.jar  ip2.xml ip2.xsl
> <?xml version="1.0" encoding="UTF-8"?>
> <networks>
> <network>
> <address>1.1.1.1</address>
> </network>
> <network>
> <address>2.3.1.2</address>
> </network>
> <network>
> <address>170.5.2.4</address>
> </network>
> </networks>
> 
> > To repeat how I did it,
> > open the XML document, go to the "XSL/XQuery"
> 
> sorry that would mean downloading xmlspy first which is too much:-)
> 
> What processor does it use for XSLT2 ?
> 
> David
> 
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-- 

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http://jroller.com/page/codecraig


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