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RE: [xsl] Can you break one node tree into two?

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Try:

<xsl:template match="RootEle">
  <xsl:variable name="a" select="Letter/Address"/>
  <RootEle>
    <Letter>
      <xsl:copy-of select="$a | $a/preceding-sibling::*"/>
    </Letter>
  <RootEle>
  <RootEle>
    <Letter>
      <xsl:copy-of select="$a/following-sibling::*"/>
    </Letter>
  <RootEle>
</xsl:template>
 
Michael Kay
http://www.saxonica.com/

> -----Original Message-----
> From: Wilde Rebecca L SSgt HQ SSG/STS 
> [mailto:Rebecca.Wilde@xxxxxxxxxxxxx] 
> Sent: 31 January 2005 21:36
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: [xsl] Can you break one node tree into two?
> 
> Hello,
> 
> I'm trying to take some XML such as:
> 
> <RootEle xmlns="">
>   <Letter>
>       <From/>
>       <To/>
>       <Address/>
>       <Subject/>
>       <Body/>
>   </Letter>
> </RootEle>
> 
> And I would like my XSLT to output:
> 
> <RootEle xmlns="">
>    <Letter>
>        <From/>
>        <To/>
>        <Address/>
>    </Letter>
> </RootEle>
> <RootEle xmlns="">
>     <Letter>
>         <Subject/>
>         <Body/>
>     </Letter>
> </RootEle>
> 
> Basically I want to say as soon as I see the Address node I want to
> break it out and everything above it into one node tree and everything
> below it into a second node tree.  The nodes could be anything, but if
> an Address node is passed to me, I need to break the node 
> tree into two.
> 
> I am think I need to do something with the xsl:copy-of and the
> xsl:for-each, but my xslt knowledge is very limited and attempting to
> use this is not creating anything near what I had hoped for.
> 
> If it isn't possible to return two node trees (which I suspect it
> isn't),  how would I make it look like: <NewRoot>
>   <RootEle xmlns="">
>     <Letter>
>        <From/>
>        <To/>
>        <Address/>
>     </Letter>
>   </RootEle>
>   <RootEle xmlns="">
>     <Letter>
>         <Subject/>
>         <Body/>
>     </Letter>
>   </RootEle>
> </NewRoot>
> 
> Thank you,
> Becky

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