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RE: [xsl] Quoting Quotes in a Stand Along Context
Subject: RE: [xsl] Quoting Quotes in a Stand Along Context From: "Michael Kay" <mike@xxxxxxxxxxxx> Date: Tue, 25 Jan 2005 23:22:49 -0000 |
XPath 1.0 doesn't define any way to escape quotes in a string literal. XPath 2.0 allows you to escape the delimiting quotes by doubling them, for example "He said: ""I don't""" You can achieve this escaping using the XPath 2.0 replace() function. Michael Kay http://www.saxonica.com/ > -----Original Message----- > From: Alan [mailto:alan-xsl-list@xxxxxxxxx] > Sent: 25 January 2005 15:47 > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: [xsl] Quoting Quotes in a Stand Along Context > > I'm writing a utility that matches nodes in a document. For > testing I'd like to simply print out a XPath statement that maps > to the node in the document. I'd like to compare that against > what I expect the output to be. > > I've got an XPath tracker in my SAX ContentHandler. It will > print something like this: > > /node()[1]/node()[4]/node()[2] > > Which ought to work, but it's hard to read. > > I'd rather emit something like this: > > /element[position() = 1 > and local-name() = 'foo' > and namespace-uri = 'http://agtrz.com/foo-doc']/text()[3] > > Easier to specify. > > But with no context to set a placeholder, I don't know how to > escape single quotes in the unlikely event that one occurs in > the namespace URI. > > How do you escape single quotes in pure XPath? > > -- > Alan Gutierrez - alan@xxxxxxxxx
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