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Re: [xsl] XPath syntax error problem

Subject: Re: [xsl] XPath syntax error problem
From: "Joe Fawcett" <joefawcett@xxxxxxxxxxx>
Date: Sat, 22 Jan 2005 17:29:15 -0000

----- Original Message ----- From: "Kenneth Stephen" <marvin.the.cynical.robot@xxxxxxxxx>
To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
Sent: Saturday, January 22, 2005 1:32 AM
Subject: [xsl] XPath syntax error problem


I have the following template in my XSL :

<xsl:template match="xsd:element">
<xsl:variable name="elementName" select="@name" />
<xsl:if test="count(//*[substring-after(@ref,':') = $elementName] = 0">
<xsl:if test="count(@name) = 1">
<xsl:if test="/xsd:schema/@elementFormDefault = 'qualified'">
<xsl:value-of select="concat($prefix,':')" />
<xsl:value-of select="@name" />

   On execution, Saxon (and Xalan too) complain about a syntax error
on the outermost "xsl:if" . The Saxon error is shown below :

bash-2.05b$ java net.sf.saxon.Transform ../data/Metadata_0101.xsd
Error at xsl:if on line 24 of
 XPath syntax error in {...(@ref,':') = $elementName] ...}:
   expected ")", found "<eof>"
Transformation failed: Failed to compile stylesheet. 1 error detected.

What am I doing wrong? What I want to do is find out if the value of the "name" attribute on an xsd:element in the input occurs within a "ref" attribute elsewhere in my XML Schema file.


You are missing a closing parenthesis: test="count(//*[substring-after(@ref,':') = $elementName] = 0" => test="count(//*[substring-after(@ref,':') = $elementName]) = 0"



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