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[xsl] XPath syntax error problem
Subject: [xsl] XPath syntax error problem From: Kenneth Stephen <marvin.the.cynical.robot@xxxxxxxxx> Date: Fri, 21 Jan 2005 19:32:58 -0600 |
Hi, I have the following template in my XSL : <xsl:template match="xsd:element"> <xsl:variable name="elementName" select="@name" /> <xsl:if test="count(//*[substring-after(@ref,':') = $elementName] = 0"> <xsl:if test="count(@name) = 1"> <xsl:if test="/xsd:schema/@elementFormDefault = 'qualified'"> <xsl:value-of select="concat($prefix,':')" /> </xsl:if> <xsl:value-of select="@name" /> </xsl:if> </xsl:if> <xsl:text>&eol;</xsl:text> </xsl:template> On execution, Saxon (and Xalan too) complain about a syntax error on the outermost "xsl:if" . The Saxon error is shown below : bash-2.05b$ java net.sf.saxon.Transform ../data/Metadata_0101.xsd analyze-schema.xsl Error at xsl:if on line 24 of file:/C:/cygwin/home/zaphod/code/analyze-schema.xsl: XPath syntax error in {...(@ref,':') = $elementName] ...}: expected ")", found "<eof>" Transformation failed: Failed to compile stylesheet. 1 error detected. What am I doing wrong? What I want to do is find out if the value of the "name" attribute on an xsd:element in the input occurs within a "ref" attribute elsewhere in my XML Schema file. Thanks, Kenneth
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