[XSL-LIST Mailing List Archive Home] [By Thread] [By Date]

Re: [xsl] XSLT2 variables / nodesets and their namespace


Subject: Re: [xsl] XSLT2 variables / nodesets and their namespace
From: David Carlisle <davidc@xxxxxxxxx>
Date: Fri, 21 Jan 2005 12:52:34 GMT

> Initially I added the namespace to the <html> tag in my output. That's
> what created all the xmlns=""s.

It seems everyone is talking about tags this morning. XSLT doesn't deel
with tags and it is that difference that is leading to the confusion.

If you just put a namespace declaration in the html start tag at the
point that you generate the html element in the result then that will
generate an html element in the xhtml namespace. Also xhtml will be the
default namespace for any other elements that are within that element
_in the stylesheet_ so if you just have <xsl:apply-templates/> there 
no other elements will be in the xhtml namespace and so if you generate
head and body in no-namespace teh system will have to add xmlns="" when
writing out a file to ensure they stay in no-namespace.
The solution is to put xmlns="xhtml namespace" on the xsl:stylesheet
element so that it is in scope for the whole stylesheet.


 <xsl:for-each select="$links/ul/li">

That selects li elements in no-namespace unless you have changed the
 default xpath namespace, and so if xhtml is the default for the whole
 stylesheet it will select nothing as

<xsl:variable name="links">
    <ul>
      <xsl:for-each select="/root/page">
        <li>


will have generated ul and li elements in the xhtml namespace.


Conversely, if you have changed the default xpath namespace to xhtml,


 <xsl:for-each select="$links/ul/li">

would select xhtml li elements but there may not be any as now in:

<xsl:variable name="links">
    <ul>
      <xsl:for-each select="/root/page">
        <li>

/root/page is selecting an element called root in the xhtml namespace
and a child called page in teh xhtml namespace. Almost certainly your
input document has no such elements, so the for-each will be over an
empty list and generate no li elements.
You will need to switch the xpath default namespace back by adding a 
xpath-default-namespace="" on the for-each.

It's probably simpler to forget aboout xpath-default-namespace and work
as in XSLT1 and always explictly prefic all element names in XPath when
they refer to an element in a namespace.

David

________________________________________________________________________
This e-mail has been scanned for all viruses by Star. The
service is powered by MessageLabs. For more information on a proactive
anti-virus service working around the clock, around the globe, visit:
http://www.star.net.uk
________________________________________________________________________


Current Thread
Keywords