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RE: [xsl] Comparing node for identity using union


Subject: RE: [xsl] Comparing node for identity using union
From: "Jim Neff" <jneff@xxxxxxxxxxxxxxx>
Date: Wed, 19 Jan 2005 09:03:38 -0500

This might be a good time for one of the gurus on this list to briefly
explain data-types in XSLT for us n00bs.

I struggle with this a lot as I am used to procedural languages that will do
data-type converstions for me.

I guess some questions that I'd like to see answered are :

How are variables typed in XSLT?  When the variable is defined or when its
used?

Will XSLT automatically convert data types?  i.e. does "2" = 2  Why or why
not?

Can I just explicity use data-type functions, like number() or string()?  Is
this a good way to do this?


Or if you can point us to resources that explains the foundations of
data-types in XSLT, that would be great.

Thanks,
Jim Neff




-----Original Message-----
From: Antsnio Mota [mailto:amsmota@xxxxxxxxx]
Sent: Wednesday, January 19, 2005 8:02 AM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Re: [xsl] Comparing node for identity using union

Well, when i say it's a bug i'm basing myself on the fact that i've tryed my
xslt with MSXML3, MSXML4, Xalan, Saxon6.5.3, Saxon8.1B, Xsltproc, and using
Javascript /Sarissa DomDocument.transformNodeTo Object and
XSLTProcessor.transformToDocument and this problem occurs ony when using
this last one. But what do i know...

The $pos is defined like

	<xsl:param name="pos" select="0"/>


and i'm passing the value from Javascript


The sugestion from Jonis also work OK

	<xsl:variable name="snode" select="(//Menu)[number($pos)]"/>


Regards.


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