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Re: [xsl] namespace-alias question

Subject: Re: [xsl] namespace-alias question
From: omprakash.v@xxxxxxxxxxxxx
Date: Tue, 18 Jan 2005 17:19:18 +0530

    Thanks for the help. I could get started with the transformation. But
the stylesheet outputted still has only the alias I gave and not 'xsl'.
I think the namespace-alias hasn't worked.

I gave the alias:

<xsl:namespace-alias stylesheet-prefix="x" result-prefix="xsl"/>

and I got:

<?xml version = '1.0' encoding = 'UTF-8'?>
<x:stylesheet version="1.0" xmlns:xsd="http://www.w3.org/2001/XMLSchema"
   <x:template xmlns:x="http://www.w3.org" match="person">
      <x:param name="root">/person</x:param> ...

Also, it works only with oracle xml parser v2 and not with xalan.

And with oraclexmlparserv2, the xsl outut contains non-printable characters
like as follows:


<several small  rectangular boxes here>

Also for any tags I create using xsl:element, it is outputting the
namespace along with the tag. Also, the schema namespace I have declared in
the source xsl is also passed to the output which I dont want.

I suppose ways exist to suppress these extra namespaces getting generated.
I would appreciate a solution for the non-printable characters and the
namespace-alias problem.

I have to mention Iam using an unknown version of xalan. The oracle parser
appears to be current.


                    Carlisle             To:     xsl-list@xxxxxxxxxxxxxxxxxxxxxx                                   
                    <davidc@xxxxx        cc:     (bcc: omprakash.v/Polaris)                                        
                    o.uk>                Subject:     Re: [xsl] namespace-alias question                           
                    08:10 PM                                                                                       
                    respond to                                                                                     

  <x:text disable-output-escaping="yes">

You don't want to use disable-output-escaping here (you almost never
want to use that).

  Here Iam using x to prefix my stylesheet while using xsl to prefix the
  stylesheet being outputted

No, you have that backwards.

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:x
xmlns:xsd="http://www.omprakashv.org" version="1.0">

Here you have defined the prefix xsl  to be
so you must use xsl: as the prefix for all teh instructions that you
want to execute such as this xsl:stylesheet element and also
You want to say that the x: prefix is an alias for XSLT so that should

<xsl:namespace-alias stylesheet-prefix="x" result-prefix="xsl"/>


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