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[xsl] super basic xsl question

Subject: [xsl] super basic xsl question
From: Jeb Boniakowski <jeb@xxxxxxxxxxx>
Date: Thu, 13 Jan 2005 11:58:56 -0500

Thanks to everyone on the list that helped me with my last problem. I still have some fundamental misunderstanding of how xsl is supposed to work, because I can't figure out how to do this:

 <child>some text</child>
 <child><a href="">a link</child>

and convert it to say...

 <li>some text</li>
 <li><a href="">a link</child>

I've tried various combos like:
<xsl:template match="child">
	<xsl:value-of select="."/>

but that means I lose the <a> tags.

I thought something with <xsl:copy> would work, but that gives me the context node, and furthermore, it doesn't give me the children, so it does the opposite. Then I thought fiddling with the 'select' expr in the value-of tag would do it, but I can't figure out if there's a magical combination of XPath slang that means, "whatever the hell is below here, be it tags or text, i want them".


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