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RE: [xsl] character replacement


Subject: RE: [xsl] character replacement
From: "Michael Kay" <mike@xxxxxxxxxxxx>
Date: Fri, 7 Jan 2005 16:47:12 -0000

> But that's strange, since translate only "replaces" a character and a
> character reference references a character (!) i went to try
>
> 	<xsl:template match="*">
> 		<xsl:copy-of select="translate(., 'b,', '&#8364;')" />
>         </xsl:template>

A character reference is just a way of inputting or outputting a character,
XPath sees the character it represents and not the original character
reference.

Incidentally, &#8364 is the Unicode Euro character. The character that you are
replacing appears to be &#x80, which is a misrepresentation of a Euro
character generated on some Microsoft systems including mine. I assume that's
why you are replacing it with the correct character...

The above code should work just fine: though whether the resulting Euro
character is represented in the output as itself or as a character reference
depends on your selected output encoding.

Michael Kay
http://www.saxonica.com/


>
> on this xml
>
> <teste>$B#b,</teste>
>
> and the output was
>
> $B#&#8364;
>
> so what was your problem?
>
> On Fri, 07 Jan 2005 16:55:26 +0100, Sven Waibel
> <sven.waibel@xxxxxxxx> wrote:
> > Thanks this helps a lot.
> >
> > Sven
> >
> > AntC3nio Mota wrote:
> >
> > > Take a look at the FAQ
> > >
> > > http://www.dpawson.co.uk/xsl/sect2/replace.html
> > >
> > > but since youre using character entitys maybe there is
> another way...
> > >
> > >
> > > On Fri, 07 Jan 2005 16:42:30 +0100, Sven Waibel
> <sven.waibel@xxxxxxxx> wrote:
> > >
> > >>Hello,
> > >>
> > >>i want to replace in my xml file all occurrences of b,
> with &#8364; because it should be display in my pdf in the right way.
> > >>
> > >>I tried it with
> > >>
> > >><xsl:template match="@*|*">
> > >>        <xsl:value-of select="translate(.,'b,','&#8364;')"/>
> > >></xsl:template>
> > >>
> > >>or
> > >>
> > >><xsl:template match="@*|*">
> > >>        <xsl:value-of select="replace(.,'b,','&#8364;')"/>
> > >></xsl:template>
> > >>but the function replace is not recognized
> > >>
> > >>Does anybody know how to get this working?
> > >>
> > >>thanks and best regards
> > >>Sven


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