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Re: [xsl] character replacement


Subject: Re: [xsl] character replacement
From: António Mota <amsmota@xxxxxxxxx>
Date: Fri, 7 Jan 2005 16:20:40 +0000

But that's strange, since translate only "replaces" a character and a
character reference references a character (!) i went to try

	<xsl:template match="*">
		<xsl:copy-of select="translate(., 'b,', '&#8364;')" />
        </xsl:template>

on this xml

<teste>$B#b,</teste>

and the output was

$B#&#8364;

so what was your problem?

On Fri, 07 Jan 2005 16:55:26 +0100, Sven Waibel <sven.waibel@xxxxxxxx> wrote:
> Thanks this helps a lot.
>
> Sven
>
> AntC3nio Mota wrote:
>
> > Take a look at the FAQ
> >
> > http://www.dpawson.co.uk/xsl/sect2/replace.html
> >
> > but since youre using character entitys maybe there is another way...
> >
> >
> > On Fri, 07 Jan 2005 16:42:30 +0100, Sven Waibel <sven.waibel@xxxxxxxx>
wrote:
> >
> >>Hello,
> >>
> >>i want to replace in my xml file all occurrences of b, with &#8364;
because it should be display in my pdf in the right way.
> >>
> >>I tried it with
> >>
> >><xsl:template match="@*|*">
> >>        <xsl:value-of select="translate(.,'b,','&#8364;')"/>
> >></xsl:template>
> >>
> >>or
> >>
> >><xsl:template match="@*|*">
> >>        <xsl:value-of select="replace(.,'b,','&#8364;')"/>
> >></xsl:template>
> >>but the function replace is not recognized
> >>
> >>Does anybody know how to get this working?
> >>
> >>thanks and best regards
> >>Sven


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