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RE: [xsl] Comparing nodes in axis

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> Is it correct to use expressions like these ones:
> 
>                         <xsl:if test="parent::menu=(//menu)[$pos]">
>                             <xsl:text>1</xsl:text>
>                         </xsl:if>
> 
>                        <xsl:if test="ancestor::menu=(//menu)[$pos]">
>                             <xsl:text>0</xsl:text>
>                         </xsl:if>
> 
> to compare the context node with another known node?

You are comparing the nodes for equality, whereas your description suggests
you want to compare them for identity. To compare whether $A and $B are the
same node, use ($A is $B) in XPath 2.0, or (count($A|$B)=1) in XPath 1.0.

Michael Kay
http://www.saxonica.com/

> 
> In the first example i'm saying
> 
> "If the context node, the one now being processed, is the 
> parent of the 
> menu node at absolute position $pos"
> 
> and
> 
> "If the the menu node at absolute position $pos is one of the 
> ancestors 
> of the context node"?
> 
> It is apparently working OK, but i never saw such comparisons 
> being made...
> 
> 
> As a side question, i tend to make things like
> 
>                         <xsl:if test="parent::menu=(//menu)[$pos]">
>                             <xsl:text>1</xsl:text>
>                         </xsl:if>
>                         <xsl:if 
> test="not(parent::menu=(//menu)[$pos])">
>                             <xsl:text>0</xsl:text>
>                         </xsl:if>
> 
> Is there any drawback in doing this insted of choose/when/otherwise?
> 
> Thanks.

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