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[xsl] Checking for instance of xs:integer
Subject: [xsl] Checking for instance of xs:integer From: Kenneth Stephen <marvin.the.cynical.robot@xxxxxxxxx> Date: Mon, 11 Oct 2004 13:01:18 -0500 |
Hi, I have the following code : <?xml version="1.0"?> <xsl:stylesheet version="2.0" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:xdt="http://www.w3.org/2003/11/xpath-datatypes" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output omit-xml-declaration="yes" /> <xsl:template match="/"> <xsl:variable name="var"> <xsl:element name="a"> <xsl:value-of select="xs:integer(2) treat as xs:integer" /> </xsl:element> </xsl:variable> <xsl:choose> <xsl:when test="$var/a instance of xs:integer"> yes </xsl:when> <xsl:otherwise> no </xsl:otherwise> </xsl:choose> </xsl:template> </xsl:stylesheet> ...where I'm trying to detect if a variable has an integer value. The output that I currently get is : bash-2.05b$ java net.sf.saxon.Transform intck.xsl intck.xsl no At first I thought that this is because the xsl:value-of that is used to assign the value of $var/a was producing either a string or an untypedAtomic value. However, changing the "xsl:when" to test for xs:string and xsd:untypedAtomic didnt work either. Is there any way to get this to work without using a schema aware processor? Thanks, Kenneth
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