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[xsl] Sorting and replacing content
Subject: [xsl] Sorting and replacing content From: "Kenny Bogoe (BogoeMD)" <kenny@xxxxxxxxx> Date: Wed, 01 Sep 2004 11:31:04 +0200 |
Hi, I have this structure where the content of tags <A> to <E> have to determine the order of tag-content <a> to <e>. The result needs to be as shown below. I can manage to make a stylesheet with an <xsl:if> for each <A> to <E> asking whether the number is 1, 2, 3, 4 or 5, but I am sure there must be a simpler way to do this. I can not use position() since the position af the tags can change in the structure. <Root> <a>10</a> <b>20</b> <c>30</c> <d>40</d> <e>50</e> ... ... <A>3</A> <B>5</B> <C>1</C> <D>2</D> <E>4</E> </Root> Result I need: <no>30</no> <!-- C = 1 has to be first with the value of c (which is 30) --> <no>40</no> <no>10</no> <no>50</no> <no>30</no> Thanks. Kenny Bogoe
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