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Re: [xsl] can you select name() of attributes?

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Hello again,

If someone else might have the same problem, I just wanted to say that I changed the solution to:
..
<xsl:template match="/">
<Output>
<xsl:for-each select="$Doc2/@*">
<xsl:copy-of select="."/>
<xsl:copy-of select="$Doc1/@*[not(name()!=name(current()))]"/>
<!-- <xsl:copy-of select="$Doc1/@*[name()=name(current())]"/>-->
</xsl:for-each>
<xsl:text>Some text in the output element</xsl:text>
</Output>
</xsl:template>

The old line is commented out. I found that the old one would copy every attribute from $Doc1 if but one attribute of the same name exists in $Doc2.

Thanks again.
Ragulf Pickaxe :-)

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