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Re: [xsl] finding position in list of siblings


Subject: Re: [xsl] finding position in list of siblings
From: "John C Cartwright" <John.C.Cartwright@xxxxxxxx>
Date: Fri, 09 Jul 2004 13:29:36 -0600

works perfectly! Thanks for the prompt response.

-- john


cknell@xxxxxxxxxx wrote:
Try this template:

<xsl:template match="BROTHER">
   <xsl:value-of select="count(preceding-sibling::*[name()='BROTHER')" />
</xsl:template>



--
=====================================================
John Cartwright
Associate Scientist
Geospatial Data Services Group
CIRES, National Geophysical Data Center/NOAA
(303) 497-6284
John.C.Cartwright@xxxxxxxx
=====================================================


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