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Re: [xsl] Generate N elements

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Dave Pawsons XSLT FAQ has useful examples of this.

http://www.dpawson.co.uk/xsl/sect2/sect21.html

There are two main approaches:
- Repetiton - using recursive templates
- a neat approach Jeni Tennison pointed out by selecting document nodes in the XSLT stylesheet and using position() to limit the number
This can be used in a for-each loop
e.g.
<xsl:variable name='thisdoc' select='.'/>
<xsl:for-each select='document("")//*[position() &lt;= $num_times]'>
<!-- use $thisdoc if you want to access main document nodes -->
<!-- do whatever you want -->
</xsl:for-each>

Kenny Bogoe (BogoeMD) wrote:

Hi,

This is probably very simple... I need to generate N elements on the fly. N
is a number in my source xml.

Source xml:
<Root>
   <data>4</data>
</Root>

Result xml:

<Root>
   <info/>
   <info/>
   <info/>
   <info/>
</Root>

Thanks,
Kenny Bogoe

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