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RE: [xsl] XSLT and PHP

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Sorry i've missed the FAQ link ?

Pierre 

-----Message d'origine-----
De : J.Pietschmann [mailto:j3322ptm@xxxxxxxx] 
Envoyé : vendredi 2 juillet 2004 21:41
À : xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Objet : Re: [xsl] XSLT and PHP

Pierre wrote:
> By the way you know how i can resolve this please 

You've probably two problems. The most serious is here:
> 		<xsl:for-each select="../../SELECT/$choice">

This is the same as expecting your PHP to produce 5 as result of
  $ex=" + 3";
  $result= 2 . $ex;
The resolution of the problem depends on what exactly gets into
$choice, if it's a single element name, try
  <xsl:for-each select="../../SELECT/*[name()=$choice]">

Check the FAQ (you've got a link already) for more on this topic,
search for "evaluate".

Note further that the way you've defined the variable $choice means
it holds a result tree fragment (RTF), which may trap you elswhere
too. Again, check the FAQ.

J.Pietschmann

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