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Re: [xsl] Get Absolute XPath

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Hi All,
    I am able to achieve this using following code

  <xsl:template name="getAbsoluteXPath">
    <xsl:param name="id"/>
    <xsl:variable name="doc" select="document('c:\abc.xml')"/>
    <xsl:for-each select="$doc//*[@id = $id]">
      <xsl:for-each select="(ancestor-or-self::*)">/*[<xsl:value-of
select="1+count(preceding-sibling::*)"/>]</xsl:for-each>
    </xsl:for-each>
  </xsl:template>

But in this case I have to pass the ID of element. Is there any other better
way? Thanks.

Sameer.


----- Original Message ----- 
From: "Samooo" <samooo_vc@xxxxxxxxxxx>
To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
Sent: Monday, June 21, 2004 12:22 PM
Subject: [xsl] Get Absolute XPath


> I am able to get the absolute XPath of an element in rendered chunk of
XML.
> The following template works fine.
>
>   <xsl:template name="getAbsoluteXPath">
>     <xsl:for-each select="ancestor-or-self::*">/*[<xsl:value-of
> select="1+count(preceding-sibling::*)"/> </xsl:for-each>
>   </xsl:template>
>
> But now I want to get the absolute XPath of an element w.r.t. the whole
> document. I have this document in say variable curDoc.
> <xsl:variable name="curDoc" select="document('c:\abc.xml')"/>
>
> But am not redering the whole document. I am rendering only a part of this
> document. When I call this GetAbsoluteXPath template, I can get correct
> XPath related to rendered chunk using above template code. But now I want
to
> get teh XPath of an element inside the whole document. Please advice. I am
> not able to explain this properly but I hope my question is clear. Thanks.
>
> Sameer.
>
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