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Re: [xsl] Problems with displaying node

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Hi,
I guess you need to use something like this. It prints
contents of all <para> nodes, whose "invisible"
attribute is not equal to 'yes'.

<xsl:template match="/document">
    <xsl:for-each select="para">
       <xsl:if test="not(@invisible = 'yes')">
           <xsl:value-of select="." />
       </xsl:if>
    </xsl:for-each>
</xsl:template>

Regards,
Mukul

--- Bertrand Sauviat <bsauviat@xxxxxxxxxxxxxx> wrote:
> In my XML, I have some <para> with an attribute or
> not. I want use this
> attribute to make a test. If the attribute is !=
> null then I don't want to
> display the contains of <para>.
> 
> Here is my XML:
> 
> <document>
> <para name="introduction">
>     Contains of the introduction
> </para>
> 
> <para name="author" invisible="yes">
>     Name of the author
> </para>
> 
> <para name="para1">
>     Contains of the para1
> </para>
> 
> <para name="interpara" invisible="yes">
>     Contains of the interpara
> </para>
> 
> </document>
> 
> In my XSL, I have make some condition on the
> @invisible like this:
> 
> <xsl:template match="//para">
> <xsl:if test="//para/@invisible!='yes'">
> <xsl:value-of select="//para"/>
> </xsl:if>
> </xsl:template>
> 
> But the output is binary..and don't take into a
> count my attribute..
> Thanks for help
> 



	
		
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