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RE: [xsl] Incrementing position in the tree midstream (Part 2)
Subject: RE: [xsl] Incrementing position in the tree midstream (Part 2) From: "Andreas L. Delmelle" <a_l.delmelle@xxxxxxxxxx> Date: Thu, 15 Apr 2004 20:37:01 +0200 |
> -----Original Message----- > From: Durston, Andrew (AGRE) > Hi, <snip /> > I am basically getting confused in how to count the occurances > down the chain of siblings (all objecttexts under all objects > under test-plan). > What exactly do you need? If, while processing an objecttext node (the objecttext matching template or an encompassing xsl:for-each) you need the number of objecttexts having a certain content ('.0-1.0'), that would be count(ancestor::test-plan/object/objecttext[.='.0-1.0']) for the number of all preceding- or following objecttexts in the document, this would become count(preceding::objecttext[.='.0-1.0']) count(following::objecttext[.='.0-1.0']) The *-sibling axes return only nodes from the same object parent (my guess is that this is one of the things causing your confusion?) xsl:number offers a very interesting and highly configurable alternative... For all objecttext nodes in the document, no matter what level <xsl:number count="objecttext[.='.0-1.0']" format="1. " level="any" /> For all objecttext nodes, starting from the current test-plan (if there are more than one in the document) <xsl:number count="objecttext[.='.0-1.0']" from="test-plan" format="1. " level="any" /> This should rid you of having to do the counting yourself (in case there are more than one test-plan in your source document, the XPath needed to feed to count() will obviously become more complicated..) Hope this helps! Cheers, Andreas
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