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RE: [xsl] Getting the first and last nodes of a sorted nodeset
Subject: RE: [xsl] Getting the first and last nodes of a sorted nodeset From: "Hansen, John" <John.Hansen@xxxxxxxxxx> Date: Wed, 7 Apr 2004 10:26:48 -0700 |
Sorry about that probably FAQ. It turned out to be easy. Here's the solution I just came up with if anyone is interested: <xsl:stylesheet xmlns:xsl='http://www.w3.org/1999/XSL/Transform' version='1.0'> <xsl:output method='html'/> <xsl:template match="/root"> <html> <xsl:for-each select="//nd"> <xsl:sort select="."/> <!-- <xsl:value-of select="."/><br/> --> <xsl:if test="position()=1"> <xsl:call-template name="get_first"> <xsl:with-param name="f"><xsl:value-of select="."/></xsl:with-param> </xsl:call-template> </xsl:if> </xsl:for-each> </html> </xsl:template> <xsl:template name="get_first"> <xsl:param name="f"></xsl:param> <xsl:for-each select="//nd"> <xsl:sort select="."/> <xsl:if test="position()=last()"> <xsl:call-template name="test_template"> <xsl:with-param name="b"><xsl:value-of select="$f"/></xsl:with-param> <!-- first element --> <xsl:with-param name="c"><xsl:value-of select="."/></xsl:with-param> <!-- last element --> </xsl:call-template> </xsl:if> </xsl:for-each> </xsl:template> <xsl:template name="test_template"> <xsl:param name="b"></xsl:param> <xsl:param name="c"></xsl:param> <xsl:value-of select="$b" /><br/> <xsl:value-of select="$c" /> </xsl:template> </xsl:stylesheet>
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Re: [xsl] Getting the first and las, Wendell Piez | Thread | RE: [xsl] Getting the first and las, M. David Peterson |
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