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Re: [xsl] centralised alphabetical order ...


Subject: Re: [xsl] centralised alphabetical order ...
From: "james walker" <jameswalkerandy@xxxxxxxxxxx>
Date: Thu, 01 Apr 2004 12:54:21 +0100

I think i get a problem with the union operator then, as the xalan server the translation is running on can't seem to cope with more than 27 unions of files in a for-each statement (it doesnt seem to have enough memory).
I am assuming when u say "><xsl:for-each select="some path that selects at least one node from each
document">
 ... select="key(..."
it would be something like <xsl:for-each select="document($nsindex/filename)/root/link | document($nsindex/filename)/root/link | document($nsindex/filename)/root/link">? as i tried something like this earlier and placed an xsl:sort after, this is when i encountered the union problem!

I forgot to say i have about 30 files which need to be searched.


From: David Carlisle <davidc@xxxxxxxxx>
Reply-To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Re: [xsl] centralised alphabetical order ...
Date: Thu, 1 Apr 2004 12:46:42 +0100

> I wanted to match all the titles in all documents under nsindex using the
> same xsl:key statement. For example, if i had 4 files with one title in each
> which started with the letter A, i would want the statement <xsl:for-each
> select="key('cat-by-firstocc', A)"> to go through all of those documents.


you can't have a single key lookup that covers more than one document.
xsl:key applies to all documents but each is indexed separately and
key() just returns nodes from the current document.

so you need to go
<xsl:for-each select="some path that selects at least one node from each
document">
 ... select="key(...

Often this isn't quite the semantic that you want, but it's the semantic
that you get:-)

David


-- http://www.dcarlisle.demon.co.uk/matthew

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