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At 2004-02-14 15:54 +0100, m.vanrootseler@xxxxxxxxx wrote:
:{)} That's the "programmer's approach" to solving the problem: throwing it in a variable and upping it by one. Many of my students come to class always trying to employ a programming approach.
May I instead suggest a hierarchical approach more consistent with XSLT:
That way (1) you aren't playing with variables and (2) the above note processing happens successfully when you have more than one note inside your parent element.
I hope this helps.
................... Ken
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RE: [xsl] position
Subject: RE: [xsl] position From: "G. Ken Holman" <gkholman@xxxxxxxxxxxxxxxxxxxx> Date: Sat, 14 Feb 2004 10:13:48 -0500 |
At 2004-02-14 15:54 +0100, m.vanrootseler@xxxxxxxxx wrote:
Thanks Ken, this works. I hadn't thought of using <xsl:number/>. The output, though, starts with '0', so the first note is numbered '0' but I solved this by putting the lot into a variable and upping it by 1.
:{)} That's the "programmer's approach" to solving the problem: throwing it in a variable and upping it by one. Many of my students come to class always trying to employ a programming approach.
May I instead suggest a hierarchical approach more consistent with XSLT:
<xsl:if test="note"> <xsl:for-each select="note"> <xsl:number level="any"/> ...other note stuff...
That way (1) you aren't playing with variables and (2) the above note processing happens successfully when you have more than one note inside your parent element.
I hope this helps.
................... Ken
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