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At 2004-02-10 11:20 -0600, Gruenewald, Terry wrote:
The design pattern is to write an identity stylesheet with just enough template rules to tweak the changes you need.
Note that XSLT will preserve your document model structure, but not your document syntax. The end result of your transformation will be entirely acceptable to another XML processor, but it may or may not be acceptable to human eyes based on the expectations of the user.
Use the following for your catch-all:
and then just write as many changes as you wish.
I hope this helps.
.............................. Ken
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Re: [xsl] xml to xml transformation
Subject: Re: [xsl] xml to xml transformation From: "G. Ken Holman" <gkholman@xxxxxxxxxxxxxxxxxxxx> Date: Tue, 10 Feb 2004 13:21:18 -0500 |
At 2004-02-10 11:20 -0600, Gruenewald, Terry wrote:
I have a problem that I'm having difficulty with (obviously). I have an xml file, and I need to transform it into another nearly identical XML file. What is the xsl for doing this?
The design pattern is to write an identity stylesheet with just enough template rules to tweak the changes you need.
Note that XSLT will preserve your document model structure, but not your document syntax. The end result of your transformation will be entirely acceptable to another XML processor, but it may or may not be acceptable to human eyes based on the expectations of the user.
Use the following for your catch-all:
<xsl:template match="@*|node()"> <xsl:copy> <xsl:apply-templates select="@*|node()"/> </xsl:copy> </xsl:template>
and then just write as many changes as you wish.
I hope this helps.
.............................. Ken
-- Public courses: upcoming world tour of hands-on XSL training events Each week: Monday-Wednesday: XSLT/XPath; Thursday-Friday: XSL-FO Washington, DC: 2004-03-15 San Francisco, CA: 2004-03-22 Hong Kong: 2004-05-17 Germany: 2004-05-24 England: 2004-06-07 World-wide on-site corporate, government & user group XML training!
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