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[xsl] Get external xml-data thru xsl

Subject: [xsl] Get external xml-data thru xsl
From: "Maasland, Tobias" <Tobias.Maasland@xxxxxxxxxxxxx>
Date: Thu, 22 Jan 2004 10:00:32 +0100


because of some stupid circumstances I need to grab a RDF - File (some sort of a newsticker) and translate it per XSL. I am a bloody beginner, so I tried 

<xsl:value-of select= "http://theComputer:8080/newsticker.rdf" />

to get the content from the RDF File. But it only gives an Error about 

ERROR: Description: Expected token 'EOF' found ':'.


Ok, now I've read, that I can only use Nodes in the select statement, so I made a xml:

<?xml version="1.0" encoding="ISO-8859-1"?>
<?xml-stylesheet type="text/xsl" href="testurl.xsl" ?>


and a XSL

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
   <xsl:template match="/">
   <xsl:variable name="contents_of_uri" select="test/uri" />
            <xsl:value-of select= "$contents_of_uri" />

But, as you surely know, this one puts only the URL out. Is there a way to get the content of the RDF - File and do some translations with it!? Or is this the absolutely wrong way? 

My main idea is to get this rdf and format it in some way.

Best regards


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