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[xsl] copy of processing instruction
Subject: [xsl] copy of processing instruction From: "Maia Zaharieva" <m.zaharieva@xxxxxxx> Date: Wed, 14 Jan 2004 17:15:12 +0100 |
hi, what i have is a xhtml document with some processing instructions in it. i want to transform it in another xhtml document with some minor changes. i want to keep the processing instructions as they are, so i thought simple copying would do the job: <xsl:template match="processing-instruction()"> <xsl:copy/> </xsl:template> but in this case i am missing the very last "?" of the processing instruction and i get something like <?pi .... > and not <?pi ... ?> could anyone please tell me what is it what i am missing here? thanks, maia XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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