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[xsl] copy of processing instruction

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hi,

what i have is a xhtml document with some processing instructions in it. i
want to transform it in another xhtml document with some minor changes. i
want to keep the processing instructions as they are, so i thought simple
copying would do the job:

<xsl:template match="processing-instruction()">
<xsl:copy/>
</xsl:template>

but in this case i am missing the very last "?" of the processing
instruction and i get something like
<?pi
....
>

and not
<?pi
...
?>

could anyone please tell me what is it what i am missing here?

thanks,
maia


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