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[xsl] copy of processing instruction

Subject: [xsl] copy of processing instruction
From: "Maia Zaharieva" <m.zaharieva@xxxxxxx>
Date: Wed, 14 Jan 2004 17:15:12 +0100


what i have is a xhtml document with some processing instructions in it. i
want to transform it in another xhtml document with some minor changes. i
want to keep the processing instructions as they are, so i thought simple
copying would do the job:

<xsl:template match="processing-instruction()">

but in this case i am missing the very last "?" of the processing
instruction and i get something like

and not

could anyone please tell me what is it what i am missing here?


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