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RE: [xsl] document() function - unknown protocol

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The document() function takes one or two arguments. These are both of the type URI, as in "http://, ftp://". So, seeing "arg:/", the document function perceives this as a new and unkown protocol, thus barfing up the error. So why are you putting this string in your template?
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Charles Knell
cknell@xxxxxxxxxx - email



-----Original Message-----
From:     Jim Nachlin <jnachlin@xxxxxxxxxxx>
Sent:     Tue, 14 Oct 2003 13:21:55 -0400 (EDT)
To:       XSL-List@xxxxxxxxxxxxxxxxxxxxxx
Subject:  [xsl] document() function - unknown protocol

Hi List,

I hope that this is an appropriate question for this list.

In trying to process an RDF foaf document [1] using the
stylesheet [2], the processor, which is members of the
javax.xml.transform package, gives an error which tells me that
the protocol "arg" is unknown in this statement:

<xsl:when test="document('arg:/ifp')/*/*/*">
  <xsl:variable name="ifp">
    <xsl:copy-of select="document('arg:/ifp')/*[1]/*[1]/*[1]"/>
  </xsl:variable>
  <xsl:apply-templates mode="output"  ...   />
</xsl:when>

or

<xsl:variable name="def"
 select="document('arg:/schema')/ns/schema[@ns=$ns]/rdf:RDF/*[@rdf:about=$this or @rdf:ID=$name or @ID=$name]"/>

and in several other places.

In looking over the documentation on document(), there is no
mention of a protocol "arg" or what this could possibly be.  It
seems that the stylesheet is trying to refer to one of the
namespace URIs.

Refs:
[1] http://www.nachlin.com/foaf.rdf
[2] http://xml.mfd-consult.dk/foaf/explorer/explorer.xsl

Thanks in advance for helping an XSL noob.

Jim



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