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RE: [xsl] select nodes with an attribute not contained within an excluding attribute

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Was looking for the XPath, sorry, didn't explicitly say that in the
original.

However i did get it working

//*[not(ancestor::*[@TemplateId])]/@id

-----Original Message-----
From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx
[mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx]On Behalf Of John Marshall
Sent: 08 October 2003 14:19
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: RE: [xsl] select nodes with an attribute not contained within
an excluding attribute


Will

  <xsl:apply-templates select="row[@TemplateId!='TemplateRow']"/>

do it?

John Marshall
Accurate Software

80 Peach Street, Wokingham, Berkshire, RG40 1XH, UK.
Tel: +44 (0)118 977 3889
Fax: +44 (0)118 977 1260
http://www.accuratesoftware.com <http://www.accuratesoftware.com>




-----Original Message-----
From: Alan Flaherty [mailto:alan@xxxxxxxxxxxxxxxxxx]
Sent: 08 October 2003 12:01
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: [xsl] select nodes with an attribute not contained within an
excluding attribute


Hi List,

I have the following sample XML case:
<doc>
	<paragraph id="Intro">

	</paragraph>
	<table>
		<row>
			<chunk id="HeaderText"/>
		</row>

		<row TemplateId="TemplatedRow">
			Item1: <chunk id="Item1"/> Item2: <chunk id="Item2"/>
		</row>

		<row>
			<chunk id="FooterText"/>
		</row>
	</table>
	<paragraph TemplateId="Quotes">
		<chunk id="QuoteHeader"/><newline/>
		<chunk id="QuoteBody"/>
	</paragraph>
	<paragraph id="Finish">

	</paragraph>
</doc>

I need to be able to *Any* elements with an Id attribute not contained
within *any* element with a TemplateId Attribute, templated items are
reported on separately.

The Idea is that the TemplateId'd elements are bound to a Data Source but
the others are not, at times it's easier to Load up the document and gather
all the non template bound Id's using the processing code just before I bind
the data to the documents rather than having to do this manually. There are
quite a few documents and this will make it all a little bit faster to do.

Regards,

Alan



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