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RE: [xsl] number continuation problem
Subject: RE: [xsl] number continuation problem From: "Andrew Welch" <AWelch@xxxxxxxxxxxxxxx> Date: Mon, 30 Jun 2003 16:49:20 +0100 |
Ok, is it possible in one xpath to do the following: <if> <node/> </if> <elseif> <node/> </elseif> <elseif> <node/> </elseif> <if/> ^^^ We are at the second <if>. I need to get the max count of <node>'s in the preceding if/elseif combination (which would be 1). I have the following xpath: count(parent::if/preceding-sibling::if [count(step) >= count(following-sibling::elseif[not(preceding-sibling::if[2])]/step)]/step) This however, counts both of the elseif/node's, so the predicate evaluates to 1 >= 2, which fails. Is there technique to get around this in xslt 1.0? cheers andrew --- Outgoing mail is certified Virus Free. Checked by AVG anti-virus system (http://www.grisoft.com). Version: 6.0.491 / Virus Database: 290 - Release Date: 18/06/2003 XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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