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Scott,
If this were XSLT/XPath, I'd suggest the 'div' operator (which you can find in any guide to XPath such as Mulberry's XSLT/XPath Quick Reference at http://www.mulberrytech.com/quickref).
Not knowing what that reference() function is, however, I can't say whether the 'div' operator will work for you. The argument you have for it doesn't look like XPath (e.g. the '#' isn't allowed in XML names, hence won't be found in true XPath location paths).
At 10:30 AM 5/21/2003, you wrote:
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Re: [xsl] Divide in an expression?
Subject: Re: [xsl] Divide in an expression? From: Wendell Piez <wapiez@xxxxxxxxxxxxxxxx> Date: Wed, 21 May 2003 11:04:59 -0400 |
Scott,
If this were XSLT/XPath, I'd suggest the 'div' operator (which you can find in any guide to XPath such as Mulberry's XSLT/XPath Quick Reference at http://www.mulberrytech.com/quickref).
Not knowing what that reference() function is, however, I can't say whether the 'div' operator will work for you. The argument you have for it doesn't look like XPath (e.g. the '#' isn't allowed in XML names, hence won't be found in true XPath location paths).
Cheers, Wendell
At 10:30 AM 5/21/2003, you wrote:
At the end of the line (below) I am using an xpath call to get the width from a in-memory xml document. I have the need to divide whatever that width comes out as by 300. Does anyone know how I can achieve this. The xml I am creating, is actually being sent to the adobe graphics server, and when I tried this:
width=\"(reference(adobe-content:myImageInfo2#/imageInfo/psd@width) / 300) it said that was not valid and not an int. Any ideas?
sb.append("\t<imageSize in=\"original\" resolution=\"72\" scalePolicy=\"doNotEnlarge\" constrainProportions=\"true\" width=\"reference(adobe-content:myImageInfo2#/imageInfo/psd/@width)\" />\n");
Thanks Scott
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